5n^2+12n-32=0

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Solution for 5n^2+12n-32=0 equation: 



5n^2+12n-32=0

a = 5; b = 12; c = -32;
Δ = b2-4ac
Δ = 122-4·5·(-32)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-28}{2*5}=\frac{-40}{10}
=-4
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+28}{2*5}=\frac{16}{10}
=1+3/5
$

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